消耗的电能W=转数n/电能表的参数N
=12转/(720转/kW·h)
=(1/60)kwh
≈0.017kwh
急需八年级下册物理测试题(人教版),带答案的
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初二物理下册(人教版)的练习题
设电流为I
PL=0.4W
UL×I=0.4W
(U-Ur)I=0.4W
(U-IR)I=0.4W
(4-10I)I=0.4
4I-10I²=0.4
10I²-4I 0.4=0
I²-0.4I 0.04=0
(I-0.2)²=0
电路中电流
I=0.2A
电阻R的电压
Ur=IR=0.2A×10Ω=2V
灯的电阻
RL=U/I-R=4V÷0.2A-10Ω=10Ω
灯的额定功率
P额=U额²/RL=(3.8V)²/10Ω=1.444W
